x^2-2x=3x+108=180

Solution for x^2-2x=3x+108=180 equation:

x^2-2x=3x+108=180

We move all terms to the left:

x^2-2x-(3x+108)=0

We get rid of parentheses

x^2-2x-3x-108=0

We add all the numbers together, and all the variables

x^2-5x-108=0

a = 1; b = -5; c = -108;
Δ = b2-4ac
Δ = -52-4·1·(-108)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{457}}{2*1}=\frac{5-\sqrt{457}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{457}}{2*1}=\frac{5+\sqrt{457}}{2}
$